gaggsye1780 gaggsye1780
  • 03-03-2018
  • Chemistry
contestada

What is the ph of a 0.015 m aqueous solution of hydrazoic acid (hn3) (ka = 1.9 x 10–5) at 25°c?

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Dejanras
Dejanras Dejanras
  • 13-03-2018
Answer is: pH value of aqueous solution of hydrazoic acid is 4,72.
Chemical reaction: N₃H + H₂O ⇄ N₃⁻ + H₃O⁺.
c(N₃H) = 0,015 M.
Ka(
N₃H) = 1,9·10⁻⁵.
[
N₃⁻] = [H₃O⁺] = x.
[
N₃H)] = 0,015 M - x.
Ka = [
N₃⁻] · [H₃O⁺] / [N₃H].
1,9·10⁻⁵= x² / 0,015 M -x.
Solve quadratic equation: x = 
[H₃O⁺] = 0,000019 M.
pH = -log
 [H₃O⁺] = 4,72.

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