hackingfaceboop6jm55 hackingfaceboop6jm55

02-04-2018
Physics

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Find the acceleration of a body whose velocity increases from 11ms-1 to 33ms-1 in 10 seconds

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sdgismep6d4p4 sdgismep6d4p4

02-04-2018

Acceleration is equivalent to the rate of change of velocity.

Calculate the difference of velocity, and divide by the total time it took for the change to happen.

[tex](33 \frac{m}{s} - 11 \frac{m}{s} ) \div 10seconds \\ = 2 \frac{m}{ {s}^{2} } [/tex]
That is the answer.

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zaidkamalkhan12 zaidkamalkhan12

02-04-2018

as we know that
a= dell V/t
then put values
a= 2ms/^2

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