Molarity is defined as the number of moles in 1 L of solution. Mass of NaNO₃ present - 85.0 g Molar mass of NaNO₃ - 85 g/mol The number of NaNO₃ moles - 85.0 g / 85 g/mol = 1 mol Volume of solution - 750 mL The number of moles in 0.750 mL - 1 mol Therefore in 1 L solution, number of NaNO₃ moles - 1/0.75 = 1.33 mol Therefore molarity of solution - 1.33 M
