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  • 04-04-2018
  • Chemistry
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A 80.0 mL volume of 0.25 M HBr is titrated with 0.50 M KOH. Calculate the pH after addition of 40.0 mL of KOH at 25 ∘C.

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ChemistryHelper2024
ChemistryHelper2024 ChemistryHelper2024
  • 13-04-2018
Number of moles of HBr = 80.0 mL x(1L / 1000 mL) x (0.25 mol / L) = 0.02 mol
Number of moles of KOH = 40.0 mL x (1 L / 1000 mL) x (0.5 mol / L) = 0.02 mol
At this point all the acid is completely neutralized by base so; at the equivalence point pH of solution equal 7 (salt of strong acid and strong base KBr) 
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