ABCD is a square. Given only the choices below, which properties would you use to prove AEB ≅ DEC by SAS? The diagonals are ⊥ to each other. Opposite sides are | |. The diagonals bisect each other. All sides are congruent.
All sides of a square re equal and opposite sides are parallel to each other. Assuming that E is the point where the diagonals intersect (since we are not told in the question), then AEB ≅ DEC. By SAS, 2 sides are equal. That is AE = EC and DE = EB. The triangles share a common angle. That is <DEC=<AEB
The property used the diagonals bisect each other.
