Answer:
[tex]\large\boxed{\dfrac{x+2}{x^2-6x-16}\div\dfrac{1}{9x}=\dfrac{9x}{x-8}}[/tex]
Step-by-step explanation:
[tex]\dfrac{x+2}{x^2-6x-16}\div\dfrac{1}{9x}=\dfrac{x+2}{x^2+2x-8x-16}\cdot\dfrac{9x}{1}\\\\=\dfrac{(x+2)(9x)}{x(x+2)-8(x+2)}=\dfrac{(x+2)(9x)}{(x+2)(x-8)}\\\\\text{cancel}\ (x+2)\\\\=\dfrac{9x}{x-8}[/tex]
